Npn BJT: Determine Mode of Operation Given Terminal Voltages

[DivGradCurl]

Homework Statement

Determine the mode of operation of this npn BJT, given the terminal voltages.

E = -0.10 V
B = 5.0 V
C = 5.0 V

Homework Equations

Below

The Attempt at a Solution

According to the general rules, the EBJ is forward biased and the CBJ is reverse biased, leading to the conclusion that the device is in active mode. However, the values obtained (more below) do not make physical meaning. I just need to confirm my impression.

V_BE = V_B - V_E = 5.0 - (-0.10) = 5.1 V

V_CE = V_C - V_E = 5.0 - (-0.10) = 5.1 V

V_BC = V_BE - V_CE = 0

A typical V_BE is 0.7 V, and just 0.5 V is enough to forward bias EBJ; 5.1 V is way too much.

Just over 0.3 V is enough to reverse bias CBJ; 5.1 V is way too much.

If you plug this into current equations, they blow up to unrealistic values; it's not physical.

Is this analysis correct?

Thanks!

 

[KataKoniK]

Yes, your analysis is correct. The values obtained for V_BE and V_CE are not physically possible for a typical BJT in active mode. This could be due to a faulty or damaged BJT or incorrect measurements. It would be helpful to double check the connections and measurements to ensure accuracy. If the values still do not make sense, it may be necessary to replace the BJT.