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Nth term test & convergence

  1. Apr 22, 2008 #1
    For a problem such as [tex]\sum[/tex] (1-3/n)^n with the sum going from 1 to infinity, the textbook shows to use the nth term test & that it diverges. However in a previous chapter the textbook had a theorem that said the limit of [tex]\sum[/tex] (1+x/n)^n will converge to e^x for any number x.

    So I'm confused. Are they using convergence in a different context or what am I missing?
     
  2. jcsd
  3. Apr 22, 2008 #2

    quasar987

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    It is (1+x/n)^n that converges to e^x, not the sum of that.

    And actually, you can use this fact to show that the series in your problem diverges. You know that (1-3/n)^n converges to e^{-3}, which is not 0, hence the series diverges.
     
    Last edited: Apr 22, 2008
  4. Apr 23, 2008 #3
    Thanks for the reply. I see that I obviously got confused ^_^.
     
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