# Nuber problem

1. Apr 15, 2005

### JamesU

What's the next line in this problem? (don't look it up and be cheap.)
1
11
21
1211
111221
312211
13112221
1113213211
31131211131221
13211311123113112211
11131221133112132113212221
3113112221232112111312211312113211
????????????????????????????????????????

Please put the answer in white, and go as many lines as you can.

2. Apr 15, 2005

### JamesU

NE1 gonna try????

3. Apr 15, 2005

### Daih

1
11
21
1211
111221
312211
13112221
1113213211
31131211131221
13211311123113112211
11131221133112132113212221
3113112221232112111312211312113211
1321132132111213122112311311222113111221131221111131221131211131231121113112221121321132132211331222113112221

The line underneath explains the line above.. e.g. 123 = one 1, one 2, one 3 = 111213... etc..

Arghh... gets tiring.... I probably made a mistake somewhere in there too... oh well, you get the jist..

4. Apr 15, 2005

### JamesU

It's not really hard, but what are all the extra 1's for in your first answer?

5. Apr 16, 2005

### Daih

I have NO idea :rofl:

6. Apr 16, 2005

### JamesU

:rofl: :rofl: :rofl: :rofl:
:rofl: :rofl: :rofl: :rofl:
:rofl: :rofl: :rofl: :rofl:
:rofl: :rofl: :rofl: :rofl:
:rofl: :rofl: :rofl: :rofl:
:rofl: :rofl: :rofl: :rofl: :rofl: :rofl: :rofl:

:rofl: :rofl: :rofl: :rofl: :rofl:
:rofl: :rofl: :rofl:
:rofl: :rofl: :rofl:
:rofl: :rofl: :rofl:
:rofl: :rofl: :rofl:
:rofl: :rofl: :rofl: :rofl: :rofl:

:rofl: :rofl: :rofl: :rofl:
:rofl: :rofl: :rofl: :rofl:
:rofl: :rofl: :rofl: :rofl:
:rofl: :rofl: :rofl: :rofl:
:rofl: :rofl: :rofl: :rofl:
:rofl: :rofl: :rofl: :rofl: :rofl: :rofl: :rofl:

7. Apr 20, 2005

### Drew888

Is it...
1321132132111213122112311311222113111221131221 :rofl:

Last edited: Apr 20, 2005
8. Apr 22, 2005

### JamesU

yes.

9. Apr 22, 2005

### PRodQuanta

Kinda fun, that one is.
I had one of my friends on that for about a week one time, trying to solve it mathematically.

10. Apr 25, 2005

### JamesU

I took some science class during the summer. Our teacher didn't have much to say, so he gave us riddles, that was one of 'em

11. Mar 22, 2009

### Slaapkopf

1
11
21
1211
111221
312211
13112221
1113213211
31131211131221
13211311123113112211
11131221133112132113212221
3113112221232112111312211312113211
1321132132111213122112311311222113111221131221
11131221131211131231121113112221121321132132211331222113112211
311311222113111231131112132112311321322112111312211312111322212311322113212221
132113213221133112132113311211131221121321131211132221123113112221131112311332111213211322211312113211
11131221131211132221232112111312212321123113112221121113122113111231133221121321132132211331121321231231121113122113322113111221131221

Last edited: Mar 22, 2009
12. Mar 23, 2009

### mabs239

Its a really good brain teser. But is there anything special about the series other than that?

13. Mar 23, 2009

### davee123

Not really. Let's see...

There's only 1 number that starts off with a 2-- all the rest start with 1 or 3. All of them end in a 1.

Each digit in the series (left-aligning them) results in a 3-or-less length repeating sequence. So the 3rd digit (say) gets stuck in a loop starting at the 8th number in the series, repeating "1", "1", "2", such that the Nth number in the sequence's 3rd digit is predictable for N>=8. Each place follows a similar pattern with a loop length of 3 or 1. The 5th digit (for example) is always 1 starting at the 9th number in the sequence. And right-aligning the numbers results in 4-or-less length repeating sequences.

For each number in the sequence, if there are A 1's, B 2's and C 3's, then A >= B >= C. The percentage occurrences of 1's, 2's, and 3's seem to be convergent to roughly 49.5%, 32%, and 18.5% respectively (looking down to about the 50th number in the sequence).

There are probably some more things on that level of interesting, but nothing unexpected.

DaveE

14. May 9, 2009

Dave