Nuclear binding energy problem

  • #1
bree1622
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What is the nuclear binding energy of N-14 in joules per mole of nuclei?
The mass deficit is 0.11278. Atomic mass is 14.00307. Total mass is 14.11585.
I keep getting stuck after converting and substituting it into the equation.
First I converted the mass deficit into kilograms. 0.11278 =1.1278 × 10^-1KG. Then I put into equation. E=mc2=1.1278 × 10^-1 kgmol × (2.998×108ms)^2 . I am not quite sure if this is right so far or what to do next. Any help is greatly appreciated. Thanks!
 

Answers and Replies

  • #2
mjc123
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First I converted the mass deficit into kilograms. 0.11278 =1.1278 × 10^-1KG.
Is that so? What is the mass of a mole of nitrogen atoms, for example?
 
  • #3
bree1622
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Is that so? What is the mass of a mole of nitrogen atoms, for example?
Is one mole of nitrogen 28g?
 
  • #4
mjc123
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I said one mole of nitrogen atoms, so the answer is 14 g, or to be more precise 14.00307 g. But the point is the same. The atomic weight is the mass in g (not kg) of 1 mole. So the mass deficit is not 1.1278 x 10-1 kg/mol.
 

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