Okay I'm taking an Individual Learning Course in Ontario for SPH4U and this is a Support question: How much energy would be required to remove one neutron from nitrogen-14 isotope, given these masses? a) N-14 isotope 14.0031 u b) N-13 isotope 13.0057 u 2. Relevant equations Knowns Electron = 0.000549 u Proton = 1.007276 u Neutron = 1.008665 u 3. The attempt at a solution Okay so the first step is to determine how many Protons and Neutrons there are: Periodic table says 7. Therefore A = 14, 13 and Z = 7 Second Step Determine what the unified mass of N-14 without its Electrons mnu1 = mN-14 - 7me mnu1 = 14.0031u - 7(0.000549) mnu1 = 13.999257 u Third Step Determine what the unified mass of N-13 by adding its Nucleus components together mnu2 = 7mp + 7mn mnu2 = 7(1.007276) + 7(1.008665) mnu2 = 14.11587 u Now we need to subtract the two to find the difference in mass |mnu1 - mnu2| = |13.999257 u - 14.11587 u| = 0.102607 u We can now convert this into the total binding energy 0.102607 u (931.5 MeV/c2/u) = 95.58 MeV/c2 If we divide this by A we will get our average Binding Energy 6.83 MeV/c2 per Nucleon When I do the same procedure for N-13 I get an answer of 7.24 Mev/c2 The back of the book completes the answer a totally separate way. It takes the unified mass of N-13 and adds a neutron to it. It then takes this value and subtracts the unified mass of N-14 to get a difference of 0.0113 u. They convert this into an average binding value of 10.5 MeV/c2. They then go on to say it would require ΔE = Δmc2 = 10.5 MeV/c2 of energy to remove one neutron from the N-14 isotope. So my questions are as follows; 1. Who is more correct for their average binding value the book or me? 2. Why is my method wrong if the book is right? 3. For either my value or the books value, the final answer would've required me to convert the MeV/c2 value into a kg equivalent, and then plugged it into the E=mc2 equation to get a proper Joules value. I appreciate any clarification you can offer.