1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Nuclear decay of banana

  1. Apr 6, 2014 #1
    1. The problem statement, all variables and given/known data

    If all of the energy from decay of the 40-K in one banana could be captured and converted into electrical energy, how many bananas would be needed to power a 100 W light bulb?

    There is 358 mg potassium-K per 100 grams of banana

    half life of potassium-40 is 1.248(3)×109 y

    2. Relevant equations

    ln(A/Ao)=-kt
    e=mc2
    k= (0.693/half-life)

    3. The attempt at a solution

    If a banana weighs 125 grams on average then there is 447.5 grams of potassium-40 in one banana.

    (358)(1.25) = 447.5g
    - - - - - - - - - - - - - -
    k=(0.693/1.248(3)×10^9 y) = 5.55×10^-10

    ln(A/Ao)=-kt
    k = 5.55×10^-10
    Ao = 447.5 g
    t=?
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Apr 6, 2014 #2

    NascentOxygen

    User Avatar

    Staff: Mentor

    That's 447.5 mg of K-40

    You'll need an equation that includes the energy of decay of the isotope.
     
    Last edited: Apr 6, 2014
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Nuclear decay of banana
  1. Nuclear decay (Replies: 3)

  2. Nuclear Decay (Replies: 2)

Loading...