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Nuclear Energy Question

  1. Apr 9, 2006 #1
    Synthesis of Pu239 from Uranium 238.

    as far as i know, this process occurs in a breeder reactor and surplus of neutrons are used to convert U238 to Pu 239 as useful fuel, since U238 is not fissionable.

    could anyone enlighten me with a nuclear equation for this process?

    thanks :)
  2. jcsd
  3. Apr 9, 2006 #2
    i think i got the answer now...

    U238 + neutron -> U239 + gamma -> Np239 + beta ->Pu239 + beta
  4. Apr 9, 2006 #3


    User Avatar

    Staff: Mentor

    Yes - neutron capture followed by two beta decays in succession. Z changes from 92 to 94, while A (239) remains unchanged.
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