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Nuclear Physics Scattering: Elastic, Inelastic etc

  1. Nov 12, 2007 #1
    I am preparing for a Nuclear Physics test. One of the homework problems asks the following: Choose the proper neutron interaction type for each of the following scenarios and explain why. Interaction types: elastic, inelastic, (n,[tex] \gamma[/tex]),(n,2n),(n,[tex] \alpha[/tex]).

    A. 10-MeV neutrons interacting with lead.
    B. Thermal neutrons interacting with gold.
    C. 1-MeV neutrons interacting with hydrogen in water.
    D. Thermal Neutrons interacting with boron-10.
    E. 6-MeV neutrons interacting with beryllium.

    Instructors answer to part A: Both elastic and inelastic scattering are possible, but inelastic is more probable; This is because there is a large amount of "excess" energy (~17.5 Mev) available in the compound nucleus, and it takes little time ([tex]<10^{-14} [/tex] sec) for a neutron to gain enough energy (~7 MeV to escape. This most likely would leave the residual nucleus at an excited state as there are so many low-lying excited states available in a Pb nucleus.

    First off, I am unsure of where he gets the 17.5 MeV. Every calculation I use gives an excess energy of about 22 MeV. This was obtained using the following formula:
    I used a table in the back of my book which gives the mass excess for different nuclei: I decided to use [tex]^{208}Pb [/tex] for the target nucleus since it is the most abundant form of Lead.

    [tex]_\Delta Q = (m_A+m_a-m_b-m_B)c^2[/tex]

    Mass excesses are:
    [tex]^{208}Pb [/tex]: -23364 [tex]\mu[/tex]u
    Neutron: 8665 [tex]\mu[/tex]u
    [tex]^{209}Pb [/tex]: -18926 [tex]\mu[/tex]u

    This gave me a result close to 12 MeV. When this is added to 10 Mev I get approximately 22 Mev.

    In any event, even if this is 22 MeV, what will determine weather or not a Neutron is ejected from the compound nucleus as opposed to just some elastic scattering or [tex]\gamma[/tex] gamma decay?
    Last edited: Nov 12, 2007
  2. jcsd
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