You have the following reactions:
4He+14N => proton + 17O(Oxygen)
1 + 2 => 3 + 4
there 4,14 and 17 is protons+neutron in the nuclear of the atoms.
1 represents 4He, 2 represents 14N and so on.
You will have two angles, theta3 and theta4, there theta3=63 degrees is the angle of the proton
relative to the alpha particle, and theta4=27 degrees is the angle of the oxygen relative to the alpha particle.
Calculate the mass of the proton with the help of the angles and also calculate the mass of 1,2 and 4 with help from tables.
The Attempt at a Solution
I have a problem here because i can't really figure out if this is an elastic or an inelastic collision.
Even if i knew that, i would like to see how to calculate the mass of the proton, i have tried assuming that it is elastic and inelastic and get wrong in both case.
Also i would like to know which data i need to see i the tables to get the others mass