- #1

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Assume we have a deuterium-tritium reaction. The energy released is 17.6 MeV. I know from solved examples that neutrons carry 14.1 MeV and Helium carries 3.5 MeV. How do I calculate these numbers (14.1 MeV and 3.5 MeV)?

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- Thread starter Dr. Octavious
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- #1

- 22

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Assume we have a deuterium-tritium reaction. The energy released is 17.6 MeV. I know from solved examples that neutrons carry 14.1 MeV and Helium carries 3.5 MeV. How do I calculate these numbers (14.1 MeV and 3.5 MeV)?

- #2

mfb

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- #3

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Looks like the energy is shared between the products inversely proportional to their mass

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