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What if we had a lithium-7 (Z=3) nucleus, say where the a proton from [itex] 1s_{1/2} [/itex]was excited (by some means) to the [itex] 2s_{1/2} [/itex] state. Now we have 2 unpaired protons, one in the [itex] 1p_{3/2}[/itex] state and the [itex] 2s_{1/2} [/itex]

what would the spin and the parity of this nucleus be??

Do we still look at the unpaired nucleon in teh outermost shell only??

In this case, then the spin would be [itex] (1/2)^+ [/itex], since the j value of the outermost nucleon in 1/2 and l=0.

(Spin and parity is given by [itex] i^{\pi} [/itex]

where i=j

and [itex] \pi = (-1)^l [/itex])