- #1

mt91

- 15

- 0

I've got two differential equations:

\[ du/dt =u(1-u)(a+u)-uv \]

\[ dv/dt = buv-cv \]

where a, b and c are constants.

I know to find the u null clines you set du/dt to 0.

\[ 0=u(1-u)(a+u)-uv \]

At this stage I know u=0 is a solution. However I'm not sure for the next null cline do I find it in terms of u or v?

So is it\[ v=-u^2 -au+u+a \]

or

Any help would be great, cheers