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Number Theory

  1. Apr 10, 2008 #1
    Let n=12^12. Find sigma(n).

    sigma(n) = the sum of the positive divisors of n.
     
  2. jcsd
  3. Apr 10, 2008 #2

    HallsofIvy

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    Okay- your serve! What have you done on this yourself?
     
  4. Apr 10, 2008 #3
    Well, I set it up:

    12^12 = (3^12)(4^12) = (3^12)(2^24)

    sigma(12^12) = (1-2^25)/(1-2) * (1-3^13)/(1-3)
     
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