- #1

AH05

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Let n=12^12. Find sigma(n).

sigma(n) = the sum of the positive divisors of n.

sigma(n) = the sum of the positive divisors of n.

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- Thread starter AH05
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- #1

AH05

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Let n=12^12. Find sigma(n).

sigma(n) = the sum of the positive divisors of n.

sigma(n) = the sum of the positive divisors of n.

- #2

HallsofIvy

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Let n=12^12. Find sigma(n).

sigma(n) = the sum of the positive divisors of n.

Okay- your serve! What have you done on this yourself?

- #3

AH05

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12^12 = (3^12)(4^12) = (3^12)(2^24)

sigma(12^12) = (1-2^25)/(1-2) * (1-3^13)/(1-3)

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