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Number Theory

  • Thread starter AH05
  • Start date
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Let n=12^12. Find sigma(n).

sigma(n) = the sum of the positive divisors of n.
 

Answers and Replies

HallsofIvy
Science Advisor
Homework Helper
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Let n=12^12. Find sigma(n).

sigma(n) = the sum of the positive divisors of n.
Okay- your serve! What have you done on this yourself?
 
4
0
Well, I set it up:

12^12 = (3^12)(4^12) = (3^12)(2^24)

sigma(12^12) = (1-2^25)/(1-2) * (1-3^13)/(1-3)
 

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