There are 'roughly' 20 numbers in every 100 that are divisible by 5. There are 'roughly' 900 three digit numbers. So there are 'roughly' 180 three digit numbers divisible by 5. That's enough off from 136 to make me agree with Defennder and Tedjin. You must be wrong.
#6
GTrax
156
10
5, 10, 15, 20, 25, 30
Its all the numbers that end in 5 or zero, and then ignore the last one (1000) because it had the temerity to posses 4 digits.
As you start building the sequence, you see the rule easy enough.
#7
serectrus
2
0
an=nth term of an AP (Arithmetic progression)
a=1st term
d=common difference
Since the 1st 3 digit no. divisible by 5 is 100
a=100
the last 3 digit no. divisible by 5 is 995
an=995
common difference (d)=5
n=no. of 3 digit nos. divisible by 5