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Homework Statement
[tex] log_4(5-x)-log_4(3-x) = 2 [/tex]
The Attempt at a Solution
[tex] log_4(5-x)-log_4(3-x) = 2 [/tex]
[tex] log_4\frac{3-x}{5-x} = 2 [/tex]
where do I go from here?
Dont know, not come across that expression before. Could you please explain.What do you know about [tex]a^\log_a x[/tex]?
[itex]log_a(b)= c[/itex] is equivalent to [itex]b= a^c[/itex]. Here, a= 4, b= (3-x)/(5- x), and c= 2.Homework Statement
[tex] log_4(5-x)-log_4(3-x) = 2 [/tex]
The Attempt at a Solution
[tex] log_4(5-x)-log_4(3-x) = 2 [/tex]
[tex] log_4\frac{3-x}{5-x} = 2 [/tex]
where do I go from here?
[itex]log_a(b)= c[/itex] is equivalent to [itex]b= a^c[/itex]. Here, a= 4, b= (3-x)/(5- x), and c= 2.