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Homework Help: Numerical analisys question

  1. May 29, 2010 #1
  2. jcsd
  3. May 29, 2010 #2

    HallsofIvy

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    To get [itex]g_1[/itex], they simply added x to both sides of [itex]x^3- x- 5= 0[/itex] to get [itex]x^3- 5= x[/itex].

    To get [itex]g_2[/itex], they added x+ 5 to both sides to get [itex]x^3= x+ 5[/itex] and took the cube root of both sides.

    To get [itex]g_3[/itex], they subtracted 5 from both sides to get [itex]x^3- x= 5[/itex], then factored, [itex]x(x^2- 1)= 5[/itex] and, finally, divided both sides by [itex]x^2- 1[/itex] to get [itex]x= 5/(x^2- 1)[/itex].
     
  4. May 29, 2010 #3
    ok i solved a similar equation:
    [tex]x^3+2x^2+4-x=0[/tex]
    [tex]g1=x^3+2x^2+4[/tex]

    why for g1 L=0.5
    how to find L for other g
    what is the meaning of L?
     
    Last edited: May 29, 2010
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