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Numerical Methods

  • #1
1,444
2
Not a hard question really..

Using 3 - digit arithmetic calculcate 4/5 + 1/3 and compute the relative error

4/5 + 1/3 = 17/15
chopping 4/5 = 0.800 and 1/3 = 0.333
0.800 + 0.333 = 1.133 (chop) 1.13
im assuming that after this point there is no chopping
relative error aboslute value of [tex] \frac{\frac{17}{15} - 1.13}{\frac{17}{15}} = 0.0033[/tex]
and the rleaitve error would be given in 3 siginificant digits?
sp 3.33 x 10^-3 is the relative error?

please tell me if i am right or wrong?

Your help is grealty appreciated!!
 

Answers and Replies

  • #2
1,444
2
AM i right in any of these by the way?

Please help/advise/suggest

thank you for your time!
 

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