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Numerical Methods

  1. Sep 26, 2005 #1
    Not a hard question really..

    Using 3 - digit arithmetic calculcate 4/5 + 1/3 and compute the relative error

    4/5 + 1/3 = 17/15
    chopping 4/5 = 0.800 and 1/3 = 0.333
    0.800 + 0.333 = 1.133 (chop) 1.13
    im assuming that after this point there is no chopping
    relative error aboslute value of [tex] \frac{\frac{17}{15} - 1.13}{\frac{17}{15}} = 0.0033[/tex]
    and the rleaitve error would be given in 3 siginificant digits?
    sp 3.33 x 10^-3 is the relative error?

    please tell me if i am right or wrong?

    Your help is grealty appreciated!!
     
  2. jcsd
  3. Sep 26, 2005 #2
    AM i right in any of these by the way?

    Please help/advise/suggest

    thank you for your time!
     
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