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Using 3 - digit arithmetic calculcate 4/5 + 1/3 and compute the relative error

4/5 + 1/3 = 17/15

chopping 4/5 = 0.800 and 1/3 = 0.333

0.800 + 0.333 = 1.133 (chop) 1.13

im assuming that after this point there is no chopping

relative error aboslute value of [tex] \frac{\frac{17}{15} - 1.13}{\frac{17}{15}} = 0.0033[/tex]

and the rleaitve error would be given in 3 siginificant digits?

sp 3.33 x 10^-3 is the relative error?

please tell me if i am right or wrong?

Your help is grealty appreciated!!