- #1

- 753

- 2

## Main Question or Discussion Point

I need to solve this implicit function of the catenary

k=cosh(k/sqrt(k^2-1))

how do i Do this in mathematica?

k=cosh(k/sqrt(k^2-1))

how do i Do this in mathematica?

- Thread starter Nusc
- Start date

- #1

- 753

- 2

I need to solve this implicit function of the catenary

k=cosh(k/sqrt(k^2-1))

how do i Do this in mathematica?

k=cosh(k/sqrt(k^2-1))

how do i Do this in mathematica?

- #2

lurflurf

Homework Helper

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FindRoot[k==Cosh[k/Sqrt[k^2-1]], {k,guess}]

Where guess is a guess of the answer.

Where guess is a guess of the answer.

- #3

Hepth

Gold Member

- 448

- 39

Plot[{k, Cosh[k/Sqrt[(k^2 - 1)]]}, {k, 0, 4}]

You can get an approximate guess to use lurflurf's suggestion, for the two roots.

FindRoot[Cosh[k/Sqrt[k^2 - 1]] - k, {k, 0.6}]

FindRoot[Cosh[k/Sqrt[k^2 - 1]] - k, {k, 2}]

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