# Nut and Elevator Question

A nut falls off of an elevator moving upwards at 3 m/s. The nut takes 5 s to hit the ground.

Q) How high was the elevator the instant the nut fell off , the answer should be 107.5 metres

i solved this a few weeks ago, now i just cant remmeber it :( casue the test is in 2 days

Ouabache
Homework Helper
Ooops... Well on the bright side, I find solving a problem more than once, reinforces the concepts I'm learning..

How about posting what you have tried so far and show where you are getting stuck? There are many here, who can help steer you in the right direction.

well i just cant reach 107.5 m
ive tried v2=v1+at
and d = v1t + 1/2 at squared, the ones that worked last time, i think im using the wrong numbers

$$v = v_0 + at$$
&
$$v^2 - v_0 = 2as$$

Integral
Staff Emeritus
Gold Member
This is pretty straight forward,
simply plug your time (5s) into

$$d = - \frac {gt^2} 2 + V_0t + h$$

What would your $V_0$ and h be?

Ouabache