- #1

Swany

- 3

- 0

FAL=

θ = 25.2 degrees

φ = 17.640 degrees

x = 1.488 meters

L = 6.2 meters

my = 90.0 kg

mL = 28.80 kg

Find the magnitude of the normal force that the wall exerts on the ladder.

NWL =

Find the magnitude of the normal force that the floor exerts on the ladder.

NFL =

I set the axis of rotation at the center of mass of the ladder, eliminating the torque due to weight. My two

positive torques are torque due to Fal and torque due to the normal force of the wall on the ladder. My two negative

torques are torque due to you on ladder and torque due to

the normal force of the ice on the ladder.