A hot air balloonist rising vertically with a constant velocity of magnitude 5m/s releases a sandbag at an instant when the balloon is 40m above the ground. After it is released the sandbag is in free fall. a) Compute the position and velocity of the sandbag at 0.25s and 1s after it is released. b) How many seconds after its release will the bag strike the ground? c)With what magnitude of velocity does it strike the ground? d) What is the greatest height above the ground that the sandbag reaches? e) sketch a-t, v-t, and y-t graphs for the motion. part a I used x = x +vo(t)+(1/2)a(t^2) and got -0.94 m for 0.25 s and -0.1 m for 1s also: I used v = vo +at and got -2.55 m/s for 0.25s and 4.8 m/s for 1s Please check answers and help me get started with what equation to use for part b.