1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Object falls, springs catch

  1. Apr 20, 2007 #1
    1. An 8-kg plunger is released from rest in the position shown and is stopped by the two nested springs; the constant of the outer spring is k1 = 3kN/m and the constant of the inner spring is k2 = 1-kN/m. If the maximum deflection of the outer spring is observed to be 150mm, determine the height h from which the plunger was released.
    Given a diagram. h is the height above the tallest spring, the outer spring. The outer spring is 90 mm higher than the inner spring.

    2. mgh=PE .5kx^2=PE spring

    3. mg(h+.15m) = .5k1(.15m^2) + .5k2(.06m^2)
    Yielding an h of 0.509m.
    Can someone inform me if this is the right path? It seems too simple...
  2. jcsd
  3. Apr 20, 2007 #2
    Theres a typo in your spring constant so can't confirm answer but work looks fine.
  4. Apr 20, 2007 #3
    sorry, k1=3kN/m and k2=10kN/m if I remember correctly. Thanks for the confirmation.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?