(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 580 N uniform rectangular sign 4.00 m wide and 3.00 m high is suspended from a horizontal, 6.00-m-long, uniform, 80-N rod as indicated in the figure below. The left end the rod is supported by a hinge and the right end is supported by a thin cable making a 30.0° angle with the vertical.

(a) Find the tension, T, in the cable.

(b) Find the horizontal and vertical components of force exerted on the left end of the rod by the hinge. (Take up and to the right to be the positive directions.)

3. The attempt at a solution

a. (580N + 80N)(3.0m) = T cos(30) (6.0m)

T= (660N)(3.0m)/(6.0m cos 30)

T=381.1N

b. Tv=T cos 30

Tv=381.1 N cos 30

Tv=330.0 N up

Fv= Tv-W

Fv= -(330.0 N - 660 N)

Fv=330 N up

Th=T sin 30

Th=381.1 N sin 30

Th= 190.6 N to left (-190.6N)

Fh=190.6 to the right

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# Homework Help: Objects in equilibruim

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