OK here's the problem: An extremely light drivable car with a mass of only 9.50 kg was built. Suppose that the wheels of the car are locked, so that the car no longer rolls. If the car is pushed up a 30° slope by an applied for of 80.0 N, the net accel. of the car is 1.64 m/s2. What is the coefficient of kinetic friction between the car and the incline? And where's what I've done: m = 9.5 W = 93.195 a = 1.64 Fnet = ma = 15.58 Fapplied = 80 Ffriction = Fapplied - Fnet = 64.46 Fperendicular = CosTheta(W) = 80.709 (also Fnormal) Fparallel = SinTheta(W) = 46.5975 Then I have: Coeff of friction = Ffriction/Fnormal = 64.46/46.5975 = 1.3833 But according to the answers my teacher gave me, and logic (that seems a little bit high for the situation), that isn't right. Please show me where I'm going wrong. Thanks.