1. The problem statement, all variables and given/known data The question asks, What is the net torque about the axle? Pictured is a square of sidelength .1 m, the pivot is placed on the bottom left corner. A force vector of magnitude 50 N points parallel to the left side and toward the pivot. Another equal force vector points north along the right side of the square. At the risk of being chastised I have included a picture. 2. Relevant equations Torque = FxR or force(moment arm) A force vector pointing toward the pivot exerts no torque. 3. The attempt at a solution Torque = (50N)(.1 m)= 5Nm Inexplicably (to me), the answer is 4.3 Nm.