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Odd Well / Quantum Tunneling

  1. Apr 25, 2017 #1

    gv3

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    1. The problem statement, all variables and given/known data
    odd-well.jpg

    An electron with a total energy of Eo = 4.4 eV is in the potential well shown above.

    1) Find the ratio of the wavelength in Region III to the wavelength in Region I.

    λ III / λI = 1.77


    2) Given that the wave function of the electron vanishes at the left boundary of Region I, what is the maximum width dof Region I such that there are no other nodes in Region I?

    .29 nm

    3)What is the minimum energy of an electron such that it can never escape the well in Region I?

    ???? eV

    2. Relevant equations
    E=hf
    T= e-2bL
    b=√(2m(U-E)/ħ2)
    R= (K1-K2)2/(K1+K2)2

    3. The attempt at a solution
    Originally i thought that i need to set the probability of the particle transmitting equal to zero. But e can never be zero. So then i tried setting the probability of the particle reflecting equal to 1 but that still didn't lead to anything. Am i missing an equation?
     
  2. jcsd
  3. Apr 25, 2017 #2

    DrClaude

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    Staff: Mentor

    Think about what it means for the particle to escape region I. Where would the particle be found then? What would be the energy of the particle after having escaped?
     
  4. Apr 25, 2017 #3

    gv3

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    It would escape if region 2. Its energy would be -.6 correct?
     
  5. Apr 25, 2017 #4

    DrClaude

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    Staff: Mentor

    The lowest energy in the diagram is 0 eV. How can the energy be negative?
     
  6. Apr 25, 2017 #5

    gv3

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    ah i was doing E-U. would it be .6 ev? ive tried that though and it was wrong. I was doing this thinking that the particle would be found in region 2. after rereading the chapter i read that we can never observe the particle in the forbidden region. so does this mean that the particle will be found in region 3?
     
  7. Apr 25, 2017 #6

    gv3

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    i got the answer keeping the above in mind. it was 3 ev. I dont get conceptually though why the energy of the particle has to equal the potential in the third well in order for the particle to get stuck in the first well.
     
  8. Apr 25, 2017 #7

    DrClaude

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    Staff: Mentor

    If you find the particle in region III, it has a minimum energy of 3 eV (plus eventual kinetic energy). Likewise, it you find it in region II, it has at least 5 eV. Therefore, if the particle has an energy < 3 eV, it can only be found in region I, hence it is trapped there.
     
  9. Apr 25, 2017 #8

    gv3

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    So shouldn't the question be what the maximum energy would be for it to be trapped in the first well? Since it cant have more than 3 eV to be stuck in the first well.
     
  10. Apr 25, 2017 #9

    DrClaude

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    Staff: Mentor

    The phrasing is a bit weird.
     
  11. Apr 25, 2017 #10

    gv3

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    Thanks for helping! :D
     
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