What are the odds of being dealt 'AA' 3 times in a row in texas holdem.
It would depend upon which layer you are and what other players got-- odds could be dependent on how you calculate them
for example if you were first player and you got A it owuld be 4/52 but if you were second player and the first player got A it would be 3/51 if first player got A but 4/51 if they did not.
From complete blind odds- a calculation could be done but I am too tired for ACT to do that now
McCurdy is wrong. Since all the other cards are hidden, the probability of AA is (4x3)/(52x51) for any one hand. The probability for 3 times in a row is that no. cubed. If you are talking about a long sequence of hands, the probability of 3 in a row some time is more complicated.
my method implied a little cheating :)
hey don't pretend it doesn't happen in cards
I Im talking about 'pocket aces' the 2 cards each player is dealt at start of round now the odds of being dealt 2 aces is 1 in 222 therefore
222*222*222 = 10,941,048 - 1 am I correct
so I basically did the equivalent of winning a small fortune on the lottery except all I won was about $50
Minor quibble. According to my calculation, the odds are 1 in 221, not 222.
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