I'd like to calculate the odds of winning the lottery. Each game has posted odds, however, my calculations give different odds. Perhaps I am not doing it right, or they use a different method, but here are my results compared to theirs: If we use #'s 0-9, and pick one number, then odds of winning are 1 in 10. Thus, I just have to buy 10 tickets, play all numbers, and will get a winner 100%. If 3 numbers are picked, then it's 10x10x10, or 000-999, thus 1:1000 correct? But, in a single Take5 game, numbers cannot repeat. Key space is 39. thus 39x38x37x36x35 = 69,090,840 To win top prize(all 5 #'s matched), their odds are 1:575,757. http://www.nylottery.org/ny/nyStore/cgi-bin/ProdSubEV_Cat_405_SubCat_337562_NavRoot_300.htm How is that calculated? Pick10 has better odds, eventhough the key space is 80. Since 20 numbers are picked(1/4), and you pick 10(1/8), top prize matches 10, you have 2x chances to win. But, that's the same odds as matching 5 to 10 if key space was 40. http://www.nylottery.org/ny/nyStore/cgi-bin/ProdSubEV_Cat_406_SubCat_337554_NavRoot_300.htm Winning Numbers Matched Per Game: 10 Prize: $500,000 Chances of Winning on one Game Panel 1:8,911,711 Isnt it 80^10? In any case, how is that any better than playing slots in Vegas or A.C.? 1c, 5c, 25c, gives more games than $1 on above. I played 1c at a casino in Vegas, and won $10; that's 1000%.