I'd like to calculate the odds of winning the lottery. Each game has posted(adsbygoogle = window.adsbygoogle || []).push({});

odds, however, my calculations give different odds. Perhaps I am not doing it right, or

they use a different method, but here are my results compared to theirs:

If we use #'s 0-9, and pick one number, then odds of winning are 1 in 10. Thus, I just have to buy 10 tickets, play all numbers, and will get a winner 100%.

If 3 numbers are picked, then it's 10x10x10, or 000-999, thus 1:1000 correct?

But, in a single Take5 game, numbers cannot repeat. Key space is 39.

thus 39x38x37x36x35 = 69,090,840

To win top prize(all 5 #'s matched), their odds are 1:575,757.

http://www.nylottery.org/ny/nyStore/cgi-bin/ProdSubEV_Cat_405_SubCat_337562_NavRoot_300.htm

How is that calculated?

Pick10 has better odds, eventhough the key space is 80. Since 20 numbers are picked(1/4), and you pick 10(1/8), top prize matches 10, you have 2x chances to win. But, that's the same odds as matching 5 to 10 if key space was 40.

http://www.nylottery.org/ny/nyStore/cgi-bin/ProdSubEV_Cat_406_SubCat_337554_NavRoot_300.htm

Winning Numbers Matched Per Game: 10

Prize: $500,000

Chances of Winning

on one Game Panel

1:8,911,711

Isnt it 80^10?

In any case, how is that any better than playing slots in Vegas or A.C.? 1c, 5c, 25c, gives more games than $1 on above. I played 1c at a casino in Vegas, and won $10; that's 1000%.

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# Odds of winnnig lottery

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