1. The problem statement, all variables and given/known data A cell of some bacteria divides into two cells every 40 minutes. The initial population is 2 bacteria. a)Find the size of the population after t hours b) Find the size of the population after 6 hours. c) When will the population reach 12? 2. Relevant equations None given. 3. The attempt at a solution taking t = time in hours, y(t) = population, we say that dy/dt = (3/2)y --- the 3/2 converts from hours to the 40 min growth period dy/y = (3/2)dt integrate.... ln(y) = (3/2)t + C --- C is arbitrary constant y = [e^( (3/2)t )] * L -- L is arbitrary constant analogous to e^C. we know that y(0) = 2, so to solve initial value problem, 2 = 1*L therefore L = 2 and the solution for part a) should be y(t) = 2 e^[(3/2)t] but this solution is unfortunately incorrect and I don't see how to fix it. Of course it holds for y(0) as it should, but it falls apart when I check other values. a friend mentioned something about "adding or subtracting a 1" somewhere but I don't see where I would do that, and even if I did I wouldn't understand the justification. Any help is appreciated, thanks!