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Solve the given initial value problem and determine at least approx. where the solution is valid:

(2x-y)dx + (2y-x)dy= o, y(1)=3

So I have My =-1 and Nx= -1

x^2-xy+ h(y) => -x+h'(y) = 2y-x => h(y)= y^2

=> x^2 -xy+ y^2

where would I go from here to solve the initial value prob?