1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

ODE question

  1. Mar 8, 2006 #1
    Ok, the question I have is attached. What I have done is found the general solution:

    (Question was seperable, so it was easy)
    y = x^2 - 2x + c

    But I don't kwow what/how to do is finding the initial conditions where there are:
    (a) No solutions
    (b) more than one solution
    (c) precisely one solutions


    Attached Files:

    • q8.JPG
      File size:
      22.5 KB
  2. jcsd
  3. Mar 8, 2006 #2


    User Avatar
    Homework Helper

    I don't see your ODE, but if that quadratic is your solution, it only takes algebra to solve the problem. Recall your quadratic equation. Your discriminant (the stuff inside the square root) will tell you about the nature of the solution. Just in case you forgot.

    1) Discriminant is positive: more than one solution
    2) Discriminant is zero: one solution
    3) Discriminant is negative: no real solution (imaginary solutions)

    Your "initial condition" is the value of "c".
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: ODE question
  1. ODE question (Replies: 1)

  2. A ode question (Replies: 2)

  3. ODE Question (Replies: 1)

  4. Question on ODEs (Replies: 0)

  5. ODE question (Replies: 9)