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xy' = y + (x^2 + y^2)^.5

Dividing thru by x and using the usual y/x substitution, I get:

y' = v + (1 + v^2)^.5 but I don't know if that is right or how to integrate the left side. The book has the answer of y + (x^2 + y^2)^.5 = Cx^2

Am I not handling the radical correctly?