- #1

Laura1321412

- 24

- 0

## Homework Statement

dy/dx= (4x sec(2y/x) +y) / x IC: y (1) = pi/4

## Homework Equations

## The Attempt at a Solution

So i can split that up into 4xsec(2y/x)/x +y/x

= 4sec(2y/x) +y/x and let v= y/x dy/dx = xdv/dx +v

4sec(2v) +v = xv' +v

4sec(2v)=xv' which is seperable

1/x dx - 1/4sec(2v) dv =0

1/xdx - cos(2v)/4 dv =0

lnx - sin(2v)/8 = C annnd going back to y/x

lnx-sin(2y/x)/8 = C and with the initial condition

-sin(2pi/4) / 8 = C

C= -1/8

So, lnx-sin(2y/x)/8=-1/8

lnx+1/8=sin(2y/x)/8

8lnx +1 = sin(2y/x)

arcsin(8lnx +1)= 2y/x

(xarcsin(8lnx +1) ) /2 = y Is what i get a solution. However this doesn't make sence because arcsin of 8lnx +1 doesn't really work....

So, im not sure where i went wrong :(