# ODE trouble

dextercioby
Homework Helper
All this time i did the calculations (all of them) on both ways...They match...Do you see why??Your formula is still not correct,though,it lacks something...

Daniel.

Aha, so my equation wasn't so "wrong" after all. It yielded the correct result :rofl: And ofcourse it should. Putting aside the mathematics isn't it totally obvious intuitivly, physically why integrating the inverse of the velocity over a distance yields the time to cover this distance? So your comment on my post instead of 'useless, and incorrect' should have been: 'well ofcourse using that formula in combination with v(x) leads to the correct result but your 'derivation' isn't that neat'.

dextercioby
Homework Helper
$$\int dt =\int\frac{dx}{v(t(x))}$$

which is different from what u've written...They're basically the same function of "x",but mine explicitely says that the "x" explicit dependence is achived implicitely...

Daniel.

dextercioby said:
$$\int dt =\int\frac{dx}{v(t(x))}$$