Yeah, yet another nimrod with absolutely no clue on how to solve problems. I seriously think I need to stick with literature... something I(adsbygoogle = window.adsbygoogle || []).push({}); actuallyget. >.<;

Anyhow, I have this problem I need to solve, but have no idea how. It's AP Physics B, so we're still based on Algebra, not Calculus. :)

Here's my problem:

Q: How deep was the Scorpion when its torpedo exploded?

Given/Background: In 1968, the attack submarine U.S.S. Scorpion mysteriously sank in the North Atlantic Ocean. On the night of October 26, 1993, CBS news aired a report on the sinking of the Scorpion with the loss of over 90 seamen. The report interviewed a United State's Navy Admiral who said the Scorpion sank itself when one of its torpedoes accidentally armed itself and exploded. The Admiral also stated that the wreck of the Scorpion was found in 11,500 of water. The evidence from the wreckage indicated that the sub. hit the ocean floor at 30 mph and took only 90 seconds to reach the ocean floor after the explosion. The U.S.S. Scorpion was 30 meters in length, 9 meters in width, and weighed (mass) 3.6 million kg. Water weighs about 1 kg per liter.

So, yeah... all I know is this: *sigh*

- The formula for finding acceleration of a body through a fluid:

a= W-R/M- a= acce. of sub. through water
- W= weight of sub.
- R= resistance of water
- m= mass of falling object through water

So far, for W, I have 352800000 Newtons (w= m x g -> w= 3.6 x [tex]10^6[/tex] x 9.8) and 3,600,000 kg for m.

... And that's all. -_-;

To tell the truth, I don't see how solving for a helps much. That and I have no idea how to solve for R (resistance of water). I know I have to take in count the time when the sub. reaches terminal velocity (so that within 90s, it's going at constant velocity - 30mph.)I have to get the answers in feet, so I know I have to go from meters to feet and thatsomethinghas to be cubed.

So, please help. I was able to get the equation and decipher what each letter represents, but I have no idea what to do, or how to proceed next!

I would really, really appreciate the help! :)

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Oh, please help

**Physics Forums | Science Articles, Homework Help, Discussion**