# Ok, I got part of this question right (Not HW)

• 2710
In summary, the conversation discusses the calculation of the average total upward force acting on a 72Kg diver who stands 2.4m away from the pivot of the diving board, 3.2m above the water. The water brings the diver to rest when his centre of mass is 1.6m below the surface of the water. The speed of the diver entering the water is calculated to be 7.92m/s. The average total upward force is calculated to be 1411N, but the answers suggest adding 706N to this value for a total of 2117N. This additional force may be related to Newton's first law, stating that every force has an equal and opposite force. However
2710
There is a diver of mass 72Kg who stands 2.4m away from the pivot of the diving board, 3.2m above the water.

"The water brings the diver to rest when his centre of mass is 1.6 m below the surface of the
water. Calculate the average total upward force acting on the diver which brings his vertical
velocity to zero."

I calculate the speed as he enters the water to be 7.92 which is correct.

u=7.92
v=0
a=?
s=1.6

a comes out to be -19.6m/s^2

F=ma

F= 72x |19.6| = 1411N

Yet, in the answers, it says that you have to plus 706 to this to get the total upward force. I understand that 706 comes from the mass(72) x g(9.8).

It tells me that 1411 is the decelarating force, and that 2117N is the toal upward force. Can I just ask, why is the extra 706 needed? Is it to do with Newtons first law, stating that every force has an equal and opposite force? But even so, doesn't the F=Ma in my calculation take care of that force?

Thanks

2710 said:
There is a diver of mass 72Kg who stands 2.4m away from the pivot of the diving board, 3.2m above the water.

"The water brings the diver to rest when his centre of mass is 1.6 m below the surface of the
water. Calculate the average total upward force acting on the diver which brings his vertical
velocity to zero."

I calculate the speed as he enters the water to be 7.92 which is correct.

u=7.92
v=0
a=?
s=1.6

a comes out to be -19.6m/s^2

F=ma

F= 72x |19.6| = 1411N

Yet, in the answers, it says that you have to plus 706 to this to get the total upward force. I understand that 706 comes from the mass(72) x g(9.8).

It tells me that 1411 is the decelarating force, and that 2117N is the toal upward force. Can I just ask, why is the extra 706 needed? Is it to do with Newtons first law, stating that every force has an equal and opposite force? But even so, doesn't the F=Ma in my calculation take care of that force?

Thanks
Big hint:
|Fnet|=|Fupwards - Fgravitation|= m |a|

:)

for your question. It is great to see you are thinking critically about the problem and trying to understand the concept behind the answer.

The extra 706N is needed because it represents the buoyant force acting on the diver. When the diver enters the water, the water exerts an upward force on him, which helps to bring him to a stop. This force is equal to the weight of the water displaced by the diver's body, according to Archimedes' principle.

In this case, the diver's body displaces a volume of water with a weight of 706N, which is equal to his weight on land. This buoyant force helps to reduce the total downward force acting on the diver, making it easier for the upward force to bring him to rest. Therefore, the total upward force needed is the decelerating force (1411N) plus the buoyant force (706N), giving a total of 2117N.

You are correct in saying that F=ma takes care of the equal and opposite force, but in this case, there are multiple forces acting on the diver (gravity, buoyancy, and the force from the water), so we need to consider all of them to get the total upward force acting on the diver.

I hope this helps to clarify the concept. Keep up the good work in your scientific thinking and problem-solving skills!

## 1. What does "Ok, I got part of this question right" mean?

"Ok, I got part of this question right" is a phrase commonly used when taking a test or quiz. It indicates that the person answering the question believes they have correctly answered at least a portion of the question.

## 2. What should I do if I only got part of the question right?

If you believe you have only answered a portion of the question correctly, it is important to carefully review the question and your answer. Look for any key words or concepts that you may have missed and try to incorporate them into your answer. If you are still unsure, ask for clarification from your teacher or a classmate.

## 3. Is it better to get part of the question right or leave it completely blank?

It is always better to attempt to answer a question, even if you are unsure or only able to answer a portion of it. This shows effort and may earn you partial credit. Leaving a question completely blank guarantees that you will receive no credit for that question.

## 4. How can I improve my ability to get more of the question right?

To improve your ability to answer questions correctly, it is important to practice active reading and critical thinking skills. This includes carefully reading and understanding the question, identifying key words and concepts, and using evidence or reasoning to support your answer. Additionally, regularly studying and reviewing material can help improve your overall understanding and retention.

## 5. Can I still do well if I only get part of the question right?

It is possible to do well on a test or quiz even if you only answer a portion of the questions correctly. The key is to focus on understanding the material and actively engaging with the questions, rather than solely focusing on getting the correct answer. Additionally, some teachers may offer partial credit for partially correct answers, so it is important to always attempt to answer every question to the best of your ability.

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