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Homework Help: Ok, simple, i know

  1. Apr 30, 2006 #1
    Im unsure on a very very basic differetiation i need for part of a question.

    Quite simply - differentiate x/4. Thats it. Or x over any number - just never knew the rule. Is it simply 1? or 4? or 1/4?

    I need to know for a question where iv to find the differential du for u = sin(x/y). Therefore i need to partially differentiate sin(x/y)
  2. jcsd
  3. Apr 30, 2006 #2


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    Dearly Missed

    Well, why not ponder the identity [itex]\frac{x}{4}=x*\frac{1}{4}[/itex] for a while?
  4. Apr 30, 2006 #3


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    Since, I don't think this is a homework problem, I'll guide you and give you the answer.
    There's a rule says that if k is a constant, then:
    (k f(x))' = k f'(x). This can be proven by using the Product Rule.
    (k f(x))' = k' f(x) + k f'(x) = 0 f(x) + k f'(x) (the derivative of a constant is 0) = k f'(x) (Q.E.D)
    So applying that rule here, we have:
    [tex]\left( \frac{x}{4} \right)' = \frac{1}{4} (x)' = \frac{1}{4}[/tex]
    You can also try the Product Rule or the Quotient Rule, both will work, but is a little bit longer.
    Can you get this? :)
  5. May 1, 2006 #4
    I'd already worked this out but thanks for that explanation - im sure it'l help in the future. Im revising for exams - it was just a silly hurdle in a question - so no, not homework. Thanks again:smile:
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