Can someone explain the Omega pointe to me? In regards to the theory of the universe collapsing?
Yes, this is true for "classical" content of the universe (i.e. pressure greater or equal to 0). As soon as you consider dark energy with p < 0, this clear relationship between geometry and fate of the universe is lost.Phobos said:In a simplified nutshell, Omega is the symbol used to represent the density of the universe. Omega = 1 is the critical density where there's just enough stuff in the universe such that all that combined gravity is enough to eventually stop the expansion of the universe. If the density is less than that (Omega < 1), then the expansion of the universe is dominant over gravity and the universe will expand forever. If the density is greater (Omega > 1) then gravity wins and the whole universe will stop expanding and then collapse back into a Big Crunch. At Omega =1, there's just enough gravity to counter-balance the expansion and things slow to a stop.
What about the resources (including time) that such a Universal Quantum Computer would need to perform Omega point computations?setAI said:it seems that Tippler's ideas don't apply to the end of the universe due to accelerated expansion- but those ideas DO seem to have relavance in quantum computing- as it appears that any Universal Quantum Computer automatically performs something like Omega point computations [by definition]