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Omega0 = 2*delta

  1. Sep 7, 2010 #1

    I found a problem that I'm not sure how to solve.

    A maintained oscillator satisfies the condition omega0=2*delta.
    Does anyone know what is the physical significance of this condition for the resonance phenomena?

    My guess is that there is no resonance, but that seems a little weird.

    Last edited: Sep 7, 2010
  2. jcsd
  3. Sep 7, 2010 #2
    Re: Resonance

    Hello John,
    Isn't omegao just a symbol for the angular frequency for which resonance occurs in that particular problem?
  4. Sep 7, 2010 #3
    Re: Resonance

    Forget about my guess.
    w0 is the natural frequency
    The resonance frequency is wr^2 = w0^2 - 2delta^2
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