Q. A chemistry student with a mass of 75 kg is riding a steadily moving Ferris wheel. When she is at the top of the Ferris wheel, the normal force from the seat on to her body has a magnitude of 556 N. Q. What would the normal force be on the student at the top of the wheel if the wheel's velocity were doubled If the wheels velocity were doubled mv^2 / R increases by a factor of four, i.e Weight of the student = 75 kg * 9.81 = 735.75 N - Normal Force ( 556 N ) = 179.75 N * 4 ( coz, it increases by a factor of 4 ) = 719 N There fore Normal force = 719 N - 735.75 N = 16.75 N , is this correct!!!!!!!