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Do all elementary particles rotate?

Without a magnetic field can you have rotation or does the rotation create the magnetic field?

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Do all elementary particles rotate?

Without a magnetic field can you have rotation or does the rotation create the magnetic field?

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ShayanJ

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It means something else. But no one knows what's that yet.Does spin for particles actually refer to spin as in rotation? Or does it mean something else.

If by rotate, you mean they have spin, no, some of them have spin zero.Do all elementary particles rotate?

But you shouldn't use rotate as having the same meaning of having spin. This is very very wrong.

Spin is an intrinsic property of particles, like their mass and charge. Now a charged particle with non-zero spin, will have a non-zero magnetic moment.(Not that neutral particles can't have magnetic moment.)Without a magnetic field can you have rotation or does the rotation create the magnetic field?

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So what is spin, rotation across an axis?It means something else. But no one knows what's that yet.

If by rotate, you mean they have spin, no, some of them have spin zero.

But you shouldn't use rotate as having the same meaning of having spin. This is very very wrong.

Spin is an intrinsic property of particles, like their mass and charge. Now a charged particle with non-zero spin, will have a non-zero magnetic moment.(Not that neutral particles can't have magnetic moment.)

Could an isolated particle just spin on its own? As in just spin aroud at one point like a dreidel?

I'm new to quantum mechanics.

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ShayanJ

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As I said, as far as I know, no one knows what is spin.So what is spin, rotation across an axis?

Could an isolated particle just spin on its own? As in just spin aroud at one point like a dradle?

But to tell you why the rotation model is wrong.

If we assume the particles are actually points, then they can't rotate around an axis passing through them. The reason is simple. When an object rotates around an axis through itself, only the points not located on the axis move. But for a point particle, there is no point not located on the axis and so there can be no rotation.

But if we assume particles have spatial extension, then it is inconsistent to model spin as rotation around an axis passing through them. Because the upper bounds we have on the size of particles, tell us that they should rotate faster than light to produce the observed effects which can't be correct.

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bhobba

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Hmmmm. Its the quantum version of angular momentum and comes from rotational symmetry exactly as the classical case - see page 82 Ballentine - QM - A Modern Development.As I said, as far as I know, no one knows what is spin.

Although not amenable to a simple analysis its fully accounted for in QFT.

It's not the same as classical angular momentum - that's true - but it is the quantum analogue of it.But to tell you why the rotation model is wrong.

Hmmmm. And if charged what happens to its electric field?If we assume the particles are actually points, then they can't rotate around an axis passing through them.

Thanks

Bill

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ShayanJ

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Hmmmm. Its the quantum version of angular momentum and comes from rotational symmetry exactly as the classical case - see page 82 Ballentine - QM - A Modern Development.

Although not amenable to a simple analysis its fully accounted for in QFT.

OK. But why particles have this form of angular momentum? What is "rotating"? That's a question that I think no one has given an answer to yet!

It seems to me that this is OP's question!

Yeah, but I meant spin is not the result of particle rotating around an axis through itself.It's not the same as classical angular momentum - that's true - but it is the quantum analogue of it.

Well, yes. That's one problem with point particles but I didn't say particles are point-like. I saidHmmmm. And if charged what happens to its electric field?

But actually, now that I think, I don't understand what you're trying to say. Could you explain?

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bhobba

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As I said there is a deep theorem in QFT that explains it.OK. But why particles have this form of angular momentum?

Nothing is rotating in a classical sense. But mathematically, as Dextercioby said, it was sorted out ages ago by Wigner to have exactly the same basis as classical mechanics - symmetry.What is "rotating"? That's a question that I think no one has given an answer to yet!

Sure - that part is true.Yeah, but I meant spin is not the result of particle rotating around an axis through itself.

I am no expert on renormalisation but I don't think the modern Wilsonian view looks at renormalisation that way. Without a cut-off you get things like the Ladau pole and we know long before that the electroweak theory takes over anyway.we treat particles as point like in QFT and use renormalization to avoid the mentioned problem.

Thanks

Bill

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ShayanJ

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As I said there is a deep theorem in QFT that explains it.

I think you're talking about irreducible representations of the Lorentz group here, right?Nothing is rotating in a classical sense. But mathematically, as Dextercioby said, it was sorted out ages ago by Wigner to have exactly the same basis as classical mechanics - symmetry.

So spin appears only because irreducible representations of Lorentz group can be classified according to it?

That's a very abstract way of looking at it!(But its good enough of course)

But to say spin is the analogous of classical angular momentum, I think we should find something to rotate, otherwise such an analogy has no reason!

Yeah, I wasn't careful in that. But as I said, I don't know much about renormalization group so I can't talk in a way which is consistent with it.I am no expert on renormalisation but I don't think the modern Wilsonian view looks at renormalisation that way. Without a cut-off you get things like the Ladau pole and we know long before that the electroweak theory takes over anyway.

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bhobba

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I am thinking of the spin-statistics theorem:I think you're talking about irreducible representations of the Lorentz group here, right?

http://en.wikipedia.org/wiki/Spin–statistics_theorem

Thanks

Bill

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ShayanJ

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I knew about that but I didn't think it can be used in this way. This theorem relates the spin of a field to the statistics it obeys. It assumes spin from the beginning. I don't think it can shed light on the nature of spin.I am thinking of the spin-statistics theorem:

http://en.wikipedia.org/wiki/Spin–statistics_theorem

Thanks

Bill

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bhobba

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It shows fields must commute or anti-commute with each other. It also shows those that commute must have integral spins and those that anti-commute have half integral spin.I knew about that but I didn't think it can be used in this way. This theorem relates the spin of a field to the statistics it obeys. It assumes spin from the beginning. I don't think it can shed light on the nature of spin.

Thanks

Bill

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ShayanJ

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Yeah, I accept. I'm reasonable enough to understand that I shouldn't oppose PF's SAs in physics issues. I'm just trying to decipher what are you referring to. As I say, I don't understand the relevance of spin-statistics theorem here. As this isn't my thread, I don't ask for clarification. But some references will do I think.The nature of spin is known already. Asking what spin is basically asking why the harmonic oscillator's hamiltonian has a discrete spectrum or why [p.q]=-ih1 holds.

Oh...I thought the theorem only says fieldsIt shows fields must commute or anti-commute with each other. It also shows those that commute must have integral spins and those that anti-commute have half integral spin.

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bhobba

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It explains why some particles are integer, and others half integer - but the commutation relations implied from symmetry considerations says it must be integer or half integer eg see page 171 Ballentine.Oh...I thought the theorem only says fieldsthatcommute have integral spin and fieldsthatanti-commute have half integral spin. I didn't know it says the first part too. But again, it seems to me its just relating commuting and anti-commuting to spin. I don't see how it can shed light on nature of spin. I was better with the irreducible representations of the Lorentz group. I really think they're relevant here. Am I wrong?

Thanks

Bill

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Now you can analyse the representations of the rotation symmetry group within quantum theory. This is a pretty mathematical and abstract subject but at the same time belongs to the most beautiful ideas in theoretical physics ever. The analysis first tells you that not the classical rotation group is the fundamental way to describe rotations in quantum theory but its covering group, the SU(2). Then the mathematics of SU(2) tells you how the irreducible unitary representations on Hilbert space look like, and the spin defines to which representation the subspace of Hilbert space of a single particle with vanishing momentum belongs (I assume massive particles here, for massless particles it's a bit more complicated). Thus it tells you how the state of a single particle at rest transforms under rotations.

That's very abstract, as I said, and it's also a bit incomplete since a concept is only physically well-defined, if we can say how to observe and even measure it somehow. Fortunately, as is well known already from classical physics, angular momentum of charged systems implies the existence of a magnetic moment, and this magnetic moment can be measured by bringing the system (or in our case a single quantum particle) into an inhomogeneous magnetic field. One of the fundamental experiments done in the history of quantum physics is the Stern-Gerlach experiment, which explcitly shows the existence of the magnetic moment of the electron (more precisely of silver atoms, but it's total spin is due to the one valence electron in the atom's outermost shell) explictly, and it turns out to be indeed a spin 1/2 particle. This is something that is not in any way observable within classical physics and thus is, as stressed above, very hard to visualize intuitively. The idea of a point-like magnetic dipole, however, is, and on an operational level one can invisage spin as such.

In addition, the spin occurs in the angular-momentum bilance of reactions, and this shows that it is indeed a kind of angular momentum in the literal sense. So, spin is very well understood in both a very abstract level and well established by observation.

As bhobba said, the best book to learn about the non-relativistic foundation of quantum theory in symmetry principles is Ballentine's book Quantum Mechanics. For the same subject in relativistic QT, see Weinberg, The Quantum Theory of Fields 1.

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