A car accelerate at -1.9 m/s2. Traveling at a constant velocity of 32 m/s, this car comes up behind a car traveling at a constant velocity of11 m/s.

a) How close to the slower car can the driver of the faster car come before applying his brakes and still avoid a collision?

b) At what time does the inevitable collision of the two cars occur?

c) How far beyond its position at t = 0 does the slower car get before it is hit?

so the |a1| = 1.9 m/s2

v1 = 32 m/s

v2 = 11 m/s.

Since it accelerates in a negative direction then it is deccelerating at a constant rate. For every second the velocity with decrease by 1.9 until it crashes with the second car with has a constant velocity. Now I dont understand what the question is asking for part a)

Can anyone help? thanks