(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A car accelerates uniformly from rest to a speed of 40 mi/h in 12.0 secs find A) the distance the car traveled during this time and B) the constant accelaration of the car

2. Relevant equations

a) Displacement of an object as a function of time: delta x =1/2(v0+v)T

B) Velocity as a function of discplacment = v^2= v0^2 + 2a delta x

3. The attempt at a solution

A) delta x = 1/2(0 + 20 m/s) 12

answer for part a = delta x = distance =120 m is this right?

B)(20 m/s)^2= 0^2 + 2a(120m)

400 m^2/s^2= 240ma

cross cancellation = answer for part b constant accelaration= 1.666666667= approx 2 m/s^2

Is this right?

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# Homework Help: One dimensional motion of car

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