One equation for three interactions->

1. Jan 17, 2004

deda

In most general sense the Archimedes' law of lever could be writen this way:

$$\frac{F_1}{F_2}=\frac{GM_1+kQ_1}{GM_2-kQ_2}=\frac{D_2}{D_1}$$
-------------------------------------------------
F=force
Q=charge
M=mass
D=equi.distance
G and k are some proportionales

Consequentially
-------------------------------------------------
$$\frac{F_1}{D_2}=\frac{F_2}{D_1}=\sqrt{\frac{G^2M_1M_2}{D_1D_2}-\frac{k^2Q_1Q_2}{D_1D_2}+kG\frac{M_2Q_1-M_1Q_2}{D_1D_2}}$$

Try this equation for this three cases:
1)$$Q_1=Q_2=0$$
2)$$M_1=M_2=0$$
3)$$M_1=Q_2=0$$
and tell me what they mean!

No matter how right my physics is it will not see day light.
That makes me really blue.

2. Jan 18, 2004

deda

well come on...*...any body got some thing to post?

3. Jan 18, 2004

Antonio Lao

Moment of Force?

Aren't you just stating the moments of forces?

another leads to Coulomb's law of static electricity.

I am still figuring out the third case.

4. Jan 18, 2004

Antonio Lao

Square of Force

After further analyses, these are what I think your formulations are:

You are claiming that there exist in the physical laws of nature, a square of force, that is proportional to the product of two different masses or the product of two different electric charges.

F^2=Gm1m2 and/or F^2=kq1q2

In my research I came across $$F^2$$. But I could not understand what it means. Now with your ideas, I will try them to see if they will help me explain the $$F^2$$ in my research. Thanks.

5. Jan 18, 2004

deda

Re: Square of Force

first in the 1st case
F1F2=G2M1M2
not as you wrote F^2=Gm1m2.
it's because:
F1=GM1
and
F2=GM2

6. Jan 18, 2004

Antonio Lao

G Squared?

Is G^2 the square of the gravitational constant?
square of 6.67x10^(-8) dyne cm^2/gm^2?

Last edited: Jan 18, 2004
7. Jan 18, 2004

deda

Re: G Squared?

It's simply a force-mass ratio.
Some N over some kg.

8. Jan 18, 2004

Antonio Lao

Can We Find This Ratio?

Can we do an experiment to find this ratio of force over mass?

9. Jan 19, 2004

deda

probably...
yes.

but any way its actual size doesn't really matter as long as you keep it same for every force-mass pair in the closed system.

10. Jan 19, 2004

Antonio Lao

Thanks. Now I can sleep peacefully.

11. Jan 26, 2004

8LPF16

dedaNoe,

Can you take a look at Antonio's thread "Is Simultaneity an Illusion?" page two?

Your force/mass ratio might be what I need, and am having trouble with.

thanks!

LPF