# One Extremly Difficult Math ?

1. Aug 23, 2009

### depathak15

y$$\diamond$$ is defined for all positive integer values of y as the product of all positive odd factors of 3y. For example, 6$$\diamond$$= 1 x 3 x 9 = 27. What is the value of 4$$\diamond$$?

I tried this question and i got it wrong. This question is on the Kaplan SAT Practice Test.
I want to know how they got the solution to this problem. Can you provide an explanation for this question???

4$$\diamond$$ would be the product of all positive odd factors of 3(4) = 12...which would be 1 x 3 = 3.