One Extremly Difficult Math ?

  • Thread starter depathak15
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In summary, the value of 4\diamond is 3. This question is from the Kaplan SAT Practice Test and the solution can be found by multiplying all the positive odd factors of 3(4) = 12, which are 1 and 3, giving a product of 3.
  • #1
depathak15
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y[tex]\diamond[/tex] is defined for all positive integer values of y as the product of all positive odd factors of 3y. For example, 6[tex]\diamond[/tex]= 1 x 3 x 9 = 27. What is the value of 4[tex]\diamond[/tex]?


Answer: 3


I tried this question and i got it wrong. This question is on the Kaplan SAT Practice Test.
I want to know how they got the solution to this problem. Can you provide an explanation for this question?

Thank You for your time...

Devansh.


BTW, I do not know where to post this question, so I decided this would be the best place...
 
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  • #2
4[tex]\diamond[/tex] would be the product of all positive odd factors of 3(4) = 12...which would be 1 x 3 = 3.
 

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