One more limit

  • Thread starter Math_Geek
  • Start date
  • #1
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Homework Statement


lim as x goes to 1 from the right of 2^1/x-1=inf


Homework Equations



solve using delta-epsilon

The Attempt at a Solution



i am not sure how to prove an infinite limit, I have a defn that states, If for epsilon>0 there exists an M>0 such that x>M implies |f(x)-L|< epsilon. My main problem is that I am not sure how to do it, and how to get the power of two out of the way
 

Answers and Replies

  • #2
229
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take the log
 
  • #3
23
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is the definition right?
 
  • #4
229
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did you mean lim x->1+ 2^(1/(1-x)) = 0?
 
Last edited:
  • #5
23
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no the problem says it goes to inf
 
  • #6
229
0
no the problem says it goes to inf

Oh it's lim x->1+ 2^(1/(x-1)), which is inf yea


The correct definition is

lim x->a+ f(x) = inf if for all M > 0 there is a d > 0 s.t. 0 < |x-1| < d and x > 1 implies |f(x)| > M
 

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