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One more limit

  1. Sep 18, 2005 #1
    this one looks simpler but i need another one of those tricks i guess:

    the limit as x-->pi/2 from the left of:

    [tex]\frac{tan x}{ln(cos x)}[/tex]

    after taking l'hopital once and simplifying i have ended up with

    [tex]\frac{1}{sin x cos x}[/tex]

    next is what i dont know
     
  2. jcsd
  3. Sep 18, 2005 #2
    wait never mind i thought of my own trick that works..multiply by 2/2 and use sin2x in the denom.
     
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