One more limit

  • #1
187
0

Main Question or Discussion Point

this one looks simpler but i need another one of those tricks i guess:

the limit as x-->pi/2 from the left of:

[tex]\frac{tan x}{ln(cos x)}[/tex]

after taking l'hopital once and simplifying i have ended up with

[tex]\frac{1}{sin x cos x}[/tex]

next is what i dont know
 

Answers and Replies

  • #2
187
0
wait never mind i thought of my own trick that works..multiply by 2/2 and use sin2x in the denom.
 

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