- #1

- 187

- 0

the limit as x-->pi/2 from the left of:

[tex]\frac{tan x}{ln(cos x)}[/tex]

after taking l'hopital once and simplifying i have ended up with

[tex]\frac{1}{sin x cos x}[/tex]

next is what i dont know

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- Thread starter thenewbosco
- Start date

- #1

- 187

- 0

the limit as x-->pi/2 from the left of:

[tex]\frac{tan x}{ln(cos x)}[/tex]

after taking l'hopital once and simplifying i have ended up with

[tex]\frac{1}{sin x cos x}[/tex]

next is what i dont know

- #2

- 187

- 0

wait never mind i thought of my own trick that works..multiply by 2/2 and use sin2x in the denom.

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