this one looks simpler but i need another one of those tricks i guess:(adsbygoogle = window.adsbygoogle || []).push({});

the limit as x-->pi/2 from the left of:

[tex]\frac{tan x}{ln(cos x)}[/tex]

after taking l'hopital once and simplifying i have ended up with

[tex]\frac{1}{sin x cos x}[/tex]

next is what i dont know

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# One more limit

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