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One-qbit quantum gates

  1. Jul 31, 2009 #1
    Hi everybody ...
    One of the one-qbit simple quantum gate is X which defined by:

    X: |0> ----- |1>
    |1> ----- |0>

    but how does this gate ( unitary operator ) act on |i> state? (i=0 or 1)
    I mean at first we have to measure what state is ( 0 or 1) and so flip them but after we know the state, it will calapse to |0> or |1>.
    so X|i>=|-i> is not correct according what I said.
  2. jcsd
  3. Jul 31, 2009 #2


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    No! Quantum gates aren't measurements* -- they are, as you said, linear operators. So the transformation of a linear combination of basis states is the linear combination of transformed basis states.

    (I'm not sure what you mean by the |i> state, can you elaborate? I worry that you have a wrong idea in your head about qubits...)

    *: at least not in the sense you're thinking. But that's quite another topic.
  4. Jul 31, 2009 #3
    yes,I know what you are saying but how does this linear operator made in real quantum computer?

    as I learnt a qbit is linear combination of two basis like a|0> + b|1> ( |a|^2 + |b|^2 = 1 ).

    I can not understand differen between linear operator and measurment as you said?
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