One question on cercular motion

[kevinlikesphysics]

just need to know what to do i keep getting different answers


[SFHS99 7.P.44.] A 13750 N car traveling at 47.0 km/h rounds a curve of radius 2.60 102 m.

(a) Find the centripetal acceleration of the car.


.66 m/s sqaured


(b) Find the force that maintains centripetal acceleration.
<this is what i can't get right here is what i got please tell me what to do>

N

9014.18

9006.38

1403.06

those are the answers i got can someone please tell me the right answer and how to get it that's a lot and equation would be nice i have been using

ma = ma(v^2)/R

(c) Find the minimum coefficient of static friction between the tires and the road that will allow the car to round the curve safely

.067 = coef.


thanks

 

[Päällikkö]

The equation you're using has a typo.
It's supposed to be ma = mv² / R (without that extra a).

a) I got a different answer (R = 102m, if I understood the numbers right?)
b) and c) Could you show what you've tried, and why?

 

[quicknote]

for your question. It seems like you are trying to solve a problem involving circular motion. The first thing you need to do is identify the known values and what you are trying to solve for. In this case, we know the mass of the car (13750 N), the velocity (47.0 km/h), and the radius of the curve (2.60 x 10^2 m). We are trying to find the centripetal acceleration (a) in part (a), the force that maintains centripetal acceleration (F) in part (b), and the minimum coefficient of static friction (μ) in part (c).

To solve for the centripetal acceleration, we can use the formula a = v^2/r, where v is the velocity and r is the radius. Make sure to convert the velocity from km/h to m/s before plugging it into the equation.

a = (47.0 km/h)^2 / (2.60 x 10^2 m) = 4.13 m/s^2

To find the force that maintains centripetal acceleration, we can use the formula F = ma, where m is the mass and a is the centripetal acceleration we just calculated.

F = (13750 N)(4.13 m/s^2) = 56787.5 N

Lastly, to find the minimum coefficient of static friction, we can use the formula μ = v^2/(rg), where v is the velocity, r is the radius, and g is the acceleration due to gravity (9.8 m/s^2).

μ = (47.0 km/h)^2 / (2.60 x 10^2 m)(9.8 m/s^2) = 0.0667

Therefore, the minimum coefficient of static friction needed for the car to safely round the curve is 0.067.

I hope this helps and clarifies any confusion you may have had. Remember to always identify the known values and what you are trying to solve for, and use the appropriate formulas to solve the problem. Good luck!