a = [62k+1] / [k-1]
a, k are natural numbers
I must find all a
what do you mean you must find all a. Through what method must you find all a?
For starters k must be even. If k is odd, k - 1 is even and 62k + 1 is odd.
I know that k must be even. But then, I calculate for k=2, k=4, k=6 .... And I have results a=63, 65, 69, 71, 83, 125 but i need good method
k-1 must divide evenly into 63. k=2,4,8,10,22.
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