# One Task

1. Nov 1, 2011

### Patronas

$$a=\frac{62k+1}{k-1}$$
or
a = [62k+1] / [k-1]

a, k are natural numbers
I must find all a

Last edited by a moderator: Nov 6, 2011
2. Nov 1, 2011

### dacruick

what do you mean you must find all a. Through what method must you find all a?

3. Nov 1, 2011

### mathman

For starters k must be even. If k is odd, k - 1 is even and 62k + 1 is odd.

4. Nov 1, 2011

### Patronas

I know that k must be even. But then, I calculate for k=2, k=4, k=6 .... And I have results a=63, 65, 69, 71, 83, 125 but i need good method

5. Nov 2, 2011

### mathman

k-1 must divide evenly into 63. k=2,4,8,10,22.

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