1. Nov 1, 2011 #1

   Patronas

   

   [tex]a=\frac{62k+1}{k-1} [/tex]
   or
   a = [62k+1] / [k-1]
   
   a, k are natural numbers
   I must find all a

    

   Last edited by a moderator: Nov 6, 2011

   Patronas, Nov 1, 2011
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3. Nov 1, 2011 #2

   dacruick

   

   what do you mean you must find all a. Through what method must you find all a?

    

   dacruick, Nov 1, 2011
4. Nov 1, 2011 #3

   mathman

   

   Science Advisor

   For starters k must be even. If k is odd, k - 1 is even and 62k + 1 is odd.

    

   mathman, Nov 1, 2011
5. Nov 1, 2011 #4

   Patronas

   

   I know that k must be even. But then, I calculate for k=2, k=4, k=6 .... And I have results a=63, 65, 69, 71, 83, 125 but i need good method

    

   Patronas, Nov 1, 2011
6. Nov 2, 2011 #5

   mathman

   

   Science Advisor

   k-1 must divide evenly into 63. k=2,4,8,10,22.

    

   mathman, Nov 2, 2011

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